This all hinges on when you count the number of problems you have. But that’s why you have two eyes! Read the same page of books 1 and 2 in parallel and obliterate 100% of your problems.
I disagree. If one book solves half of your problems at random and the other does the same, that’s still 75% on average, and 25% on average will have 2 solutions.
No you can solve 3/4ths of your problems
Zeno’s problem.
if you learn how to solve zeno’s problem in the first book, it may be possible to solve 100% of your problems in the second book
Would that make Zeno’s Wank just a type of edging?
Yes.
This all hinges on when you count the number of problems you have. But that’s why you have two eyes! Read the same page of books 1 and 2 in parallel and obliterate 100% of your problems.
I disagree. If one book solves half of your problems at random and the other does the same, that’s still 75% on average, and 25% on average will have 2 solutions.
If you buy 5 books, you’ll be able to solve 96.88% of your problems.
Or you could just read the one book eight times for 99.6℅. Why buy more than one when one is enough to read as many times as you like?
Well guess what? That was an e-book and you only get to read once.
that’s some mighty fine fiscal responsibility, right there