haroldstork@lemm.ee to Lemmy Shitpost@lemmy.worldEnglish · 18 days agomathpostingfiles.catbox.moeimagemessage-square10fedilinkarrow-up154arrow-down10
arrow-up154arrow-down1imagemathpostingfiles.catbox.moeharoldstork@lemm.ee to Lemmy Shitpost@lemmy.worldEnglish · 18 days agomessage-square10fedilink
minus-squareCreatingMachines@fedia.iolinkfedilinkarrow-up5·18 days agoLeaving a comment to remember to check this post again, in case someone drops the answer to this.
minus-squareLeate_Wonceslace@lemmy.dbzer0.comlinkfedilinkEnglisharrow-up2·edit-218 days agoNo, it’s the integers Mod 2 (Notation “Z/2Z” where Z is the Integers) which is the only group of order 2 and the smallest non-trivial field.
minus-squareMBM@lemmings.worldlinkfedilinkarrow-up4·edit-218 days agoUnless you know algebraic topology it’s kind of hopeless (but that’s the joke). If you’re curious, it’s the first example on the page on cohomology rings. Edit: So, you could say H●(🌭;🍔) = 🍔[🥚] / (🥚n+1) where |🥚| = 1.
Leaving a comment to remember to check this post again, in case someone drops the answer to this.
🍪 = 2
🍔 = 1/2
No, it’s the integers Mod 2 (Notation “Z/2Z” where Z is the Integers) which is the only group of order 2 and the smallest non-trivial field.
🍕 = –1/12
Unless you know algebraic topology it’s kind of hopeless (but that’s the joke). If you’re curious, it’s the first example on the page on cohomology rings.
Edit: So, you could say H●(🌭;🍔) = 🍔[🥚] / (🥚n+1) where |🥚| = 1.