ickplant@lemmy.world to Lemmy Shitpost@lemmy.world · 1 year agoPaniki.postimg.ccimagemessage-square41fedilinkarrow-up1805arrow-down129
arrow-up1776arrow-down1imagePaniki.postimg.ccickplant@lemmy.world to Lemmy Shitpost@lemmy.world · 1 year agomessage-square41fedilink
minus-squareAccountMaker@slrpnk.netlinkfedilinkarrow-up0·edit-21 year agoBut what about 14, 21 and 28? 14 - 4*2 = 6, not divisible by 7 21 - 1*2 = 19, not divisible by 7 28 - 8*2 = 12, not divisible by 7 Or did I misunderstand the algorithm? EDIT: I didn’t realize that you remove the last digit when subtracting, got corrected in the replies.
minus-squareColalextrast@lemmynsfw.comlinkfedilinkEnglisharrow-up1·edit-21 year agoIt goes like this create 2 distinct numbers by isolating the last digit from the other. For example, 154 becomes 15 and 4. double the number derived from the last digit. So, the four becomes 8. subtract from the number derived from the preceeding digits. 15 - 8. the resulting number is 7. Seven is divisible by 7, so we know 154 is divisible by 7.
But what about 14, 21 and 28?14 - 4*2 = 6, not divisible by 721 - 1*2 = 19, not divisible by 728 - 8*2 = 12, not divisible by 7Or did I misunderstand the algorithm?EDIT: I didn’t realize that you remove the last digit when subtracting, got corrected in the replies.
It goes like this
create 2 distinct numbers by isolating the last digit from the other. For example, 154 becomes 15 and 4.
double the number derived from the last digit. So, the four becomes 8.
subtract from the number derived from the preceeding digits. 15 - 8.
the resulting number is 7. Seven is divisible by 7, so we know 154 is divisible by 7.