no way this is real
It is and it has become a meme since then. Just search for Yandere simulator / Yanderedev.
I’ve heard about his notoriously bad code, but I didn’t think it was to this extent…
It gets worse. I am not kidding.
From what I’ve heard about yanderedev… it’s possible this is actually real.
Wow. Amateur hour over here. There’s a much easier way to write this.
A case select:
select(number){ case 1: return false; case 2: return true; }And so on.
Just do a while loop and subtract 2 if it’s positive or plus 2 is it’s negative until it reaches 1 or 0 and that’s how you know, easy! /s
God, it’s so obvious, you can do it in only two lines of code.
if (number == 1 || number == 3 || number == 5 || number == 7 || number == 9...) return false; else return true;
Oh man, in js we have a package for this magic.
I always forget if is even requires is odd or the other way around.
Look at the downloads though!
Recently there was a thread trying to declare PHP obsolete.
Hard to beat this in efficiency:
function is_even($num) { return $num % 2 === 0; }That said, this should work similarly in most languages.
Except maybe in C++ where the makers must have found some bit-fucking method that saves 0.02ms
If the language you are using uses “real” integers, using a bit mask to get the least significant bit is probably a lot faster - assuming the compiler doesn’t replace the operation for you, in which case it doesn’t matter.
They call me a StackOverflow expert:
private bool isEven(int num) { if (num == 0) return true; if (num == 1) return false; if (num ＜ 0) return isEven(-1 * num); return isEven(num - 2); }StackoverflowException.
What do I do now?
Nvm. Got it.
if(num % 2 == 0){ int num1 = num/2 int num2 = num/2 return isEven(num1) && isEven(num2) } if(num % 3 == 0){ int num1 = num/3 int num2 = num/3 int num3 = num/3 return isEven(num1) && isEven(num2) && isEven(num3) }Obviously we need to check each part of the division to make sure if they are even or not. /s
You have to make it easy on yourself and just use a switch with default true for evens, then gandle all the odd numbers in individual cases. There, cut your workload in half.
This is your brain on python:
def is_even (num): return num in [x*2 for x in range(sys.maxsize / 2)]That won’t work tho, you need to make it sys.maxsize//2 to coerce the output into int form
Ok looks like this might be the source, and I suspect it is actually satirical. Not yanderedev, but yeah… wouldn’t put it past him.
https://www.reddit.com/r/ProgrammerHumor/comments/i15h4d/iseven/
Good job my young padawan, let me teach you about the modulo operator …
Actually the modulo operator is the wrong solution.
No its not the wrong solution! Premature optimization is a waste of time.
Using if or case are not a solution because they are way too verbose and very easy to introduce an error.
Modulo is a solution, and using bit-wise and is another faster solution.
You call it premature optimization. I call it obvious.
You use a flat head as a Phillip’s.
I call it making assumptions that may be incorrect, and do you know if the compiler will do the optimization anyway in this case?
What statement do you flag as assumption? Yes, I do. The modulo operator is only a subset of bit masks. It is more explicit to write:
if ( (variable &EVEN_MASK) == 0) …
To act upon even numbers then:
if ( (variable %2) == 0) …
How would you name the 2 in the above statement for more expressive power?
EVEN_MODULO_OP ? That may throw more people off imo.
I give up, I was wrong to even think about the modulo operator, you are clearly the master programmer. 🥇
This reminds me of a discussion about the ternary operator
? :, some people think its the one true way of writing code because its just so clear what it does. And I say please use it sparingly because if you start doing nested ternary operators its very hard to unpack what your code does, and I prefer readability over compact code, especially with today’s compilers.You shouldn’t rename 2 at all. “Even” has a commonly understood meaning that is instantly recognizable from
(variable %2) == 0. The bitmask is an overgeneralization.
OMG they can’t even!
string taco = variable.ToString()[variable.ToString().Length - 1];
If (taco == “0” || taco == “2” || taco == “4” || taco == “6” || taco == “8”)
return true;
else
return false;
Im something of a coding master myself
We’re too swamped for that kind of thinking. Just keep typing or we’ll never make our release window
Modulus equals zero anyone?
The number of comments posting a better solution is funny and somewhat concerning.
Yeah, “just use modulo” - no shit, you must be some kind of master programmer
